Math 486  Game Theory. Miderm 3.  April 21, 2011.
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Find the equilibria in pure strategies, the pure Pareto optimal payoffs,
the characteristic function,  the Shapley values, and the Nash bargaining solution.

1 (30 pts).   Players: the row player Ann; the column player Bob.

 0, 1 1, 0 0, 0 1, 3 1, 1 2, 3 2, 2 2, 3 0, 3 0, 0 1, 3 3, 3 1, 0 0, 0 0, 0 1, 4

Solution.   Two  equilibriua in pure joint strategies, (row 2, column 2; row 3, column 4):

 0, 1 1, 0 0, 0 1, 3* 1*, 1 2*, 3* 2*, 2 2, 3* 0, 3* 0, 0 1, 3* 3*, 3* 1*, 0 0, 0 0, 0 1, 4*

Two Pareto optimal pure payoffs: (3, 3) and (1,4).

v(Ann)  is the value of the  following matrix game

 0 1* 0 1 1*' 2* 2* 2 0 0 1 3* 1 0 0 1

There is a saddle point, row 2 column 1, so v(Ann) = 1.

v(Bob) = 3 = the value of the matrix game (where Bob is the row player)

 1* 1 3 0' 0’ 3 0' 0' 0’ 2* 3 0’ 3* 3 3*' 4*

v(empty)=0, v(Ann,Bob) = 6.

Nash bargaining:   (u-1)(v-3)  -> max , u >= 1, v >= 3,    (u, v) is a mixture of  (3, 3) and (1,4).,
u + 2v =9,    (u – 1) + 2(v – 3) =2,  (u-1)= 2( v -3)=1;  u=2, v=3.5  optimal solution= Nash solution=   the arbitration pair.

This arbitration pair is a mixture of given payoffs: (2, 3.5) =(1/2)(1, 4) + (1/2)(3.3).

Ann          Bob

Ann Bob                   1          5

Bob Ann                   3          3

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Shapley values         2         4

2 (45 pts).   Players: A, B, C
strategies             payoffs
1  1  1                      2  3  2
1  1  2                      1  0  1
1  2  1                      2  3  3
1  2  2                      1  2  3
2  1  1                      0  0  1
2  1  2                      1  1  1
2  2  1                      2  3  3
2  2  2                      2  3  2
3  1  1                      0  0  0
3  1  2                      0  0  0
3  2  1                      1  1  1
3  2  2                      2  3  0

Solution.
Three equilibria and one Pareto optimal triple (2,3,3):
strategies                     payoffs
1  1  1                      2* 3*  2*  equilibrium  strategy
1  1  2                      1  0  1
1  2  1                      2*  3*  3*  equilibrium &  Pareto optimal
1  2  2                      1  2  3
2  1  1                      0  0  1
2  1  2                      1  1  1
2  2  1                      2*  3*  3*equilibrium &  Pareto optimal
2  2  2                      2  3  2
3  1  1                      0  0  0
3  1  2                      0  0  0
3  2  1                      1  1  1
3  2  2                      2   3 0

v(empty)=0, v(A,B,C)) = 8.

v(A) = 1 = the value of the matrix game

 2 1*' 2 1 0 1 2 2 0 0 1 2

v(B) = 1 = the value of the matrix game

 3 0 0 1 0 0 3 2 3 3 1*' 3

v(C) = 0 = the value of the matrix game

 2 3 1 3 0*' 1 1 3 1 2 0 0

v(A,B) = 5= the value of the matrix game

 5 1 5 3 0 2 5 5*' 0 0 2 5

v(A,C) = 4= the value of the matrix game

 4*' 5* 2 4 1 5 2 4 0 2 0 2

v(B,C) = 3 = the value of the matrix game

 B&C vs A c1 c2 c3 r11 5 1 0 r12 1 2 0 r21 6 6 2 r22 5 5 3*'

order         contribution
A   B   C
ABC          1   4   3
ACB          1   4   3
BAC          4   1   3
BCA          5   1   2
CAB          4   4   0
CBA          5   3   0
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10/3 17/6  11/6    Shapley values.

The Nash solution is (2, 3, 3)., the only Pareto optimal payoff.