MATH 251 EXAM I, SPRING 2003
Solutions
i. linear, order 2
ii. nonlinear, order 1
iii. linear, order 3
iv. nonlinear, order 2
A
C
C
D
(a) equilibrium solutions: y = -2, 0, 2
(b)
y = -2, (asymptotically) stable
y = 0, unstable
y = 2, (asymptotically) stable
(c) y(t) = 2
(a) Q(t) = -6e-t/200 + 6
(b) it will never happen (or, when t approaches infinity)
(b) x ln(y) + x2y + sin(2x) = C
(a) yes
(b) yes: W(y1,y2) = -4t, which is not equal to zero when t is not zero
(c) since y1 and y2 are two linearly independent solutions, the general solution is therefore y(t) = C1t3 + C2t -1
(a) y(t) = C1e-4t + C2et
(b) y(t) = C1e-4t + C2et - 3cos(2t) - 4sin(2t)
y(t) = 3e-3t + 8te-3t